A magnet hung at 45 ° with magnetic meridian makes an angle of 60 ° with the horizontal. The actual value of the angle of dip is

Step-by-step solution

Given here, θ ' = 60 ° and apparent value of dip, α = 45 ° . If H is horizontal component of earth's magnetic field in magnetic meridian, then tan θ ' = V H . Let H 1 be component of H at 60 ° to magnetic meridian, then tan θ = V H 1 = V H cos α = tan θ ' cos α tan θ = tan 60 ° × cos 45 ° ⇒ tan θ = 3 × 1 2 Thus, the actual value of the angle of dip is θ = tan - 1 3 2