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JEE Main20204 Sep 2020Evening ShiftPhysicsMagnetic Properties of MatterActual

A paramagnetic sample shows a net magnetisation of 6 A / m when it is placed in an external magnetic field of 0 . 4 T at a temperature of 4 K . When the sample is placed in an external magnetic field of 0 . 3 T at a temperature of 24 K , then the magnetisation will be :

Options

  1. A1   A / m
  2. B4   A / m
  3. C2 . 25   A / m
  4. D0 . 75   A / m

Correct answer

D. 0 . 75   A / m

Step-by-step solution

According to Curie's Law, χ ∝ 1 T Therefore, χ 1 T 1 = χ 2 T 2 Also, χ = M B So, M 1 T 1 B 1 = M 2 T 2 B 2 On substituting the values, 6 × 4 0 . 4 = M 2 × 24 0 . 3 Therefore, M 2 = 0 . 75   A   m - 1

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