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JEE Main 201911 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
11 January
Shift
Evening Shift
Subject
Physics
Chapter
Magnetic Properties of Matter

JEE Main 2019 · 11 January · Evening Shift · Physics · Magnetic Properties of Matter

A paramagnetic substance in the form of a cube with sides 1 ~cm has...

A paramagnetic substance in the form of a cube with sides 1 cm1 \mathrm{~cm} has a magnetic dipole moment of 20×10−6 J/T20 \times 10^{-6} \mathrm{~J} / \mathrm{T} when a magnetic intensity of 60×103 A/m60 \times 10^{3} \mathrm{~A} / \mathrm{m} is applied. Its magnetic susceptibility is:

Options

  1. A3.3×10−23.3 \times 10^{-2}
  2. B4.3×10−24.3 \times 10^{-2}
  3. C2.3×10−22.3 \times 10^{-2}
  4. D3.3×10−43.3 \times 10^{-4}

Correct answer

D. 3.3×10−43.3 \times 10^{-4}

Step-by-step solution

Magnetic susceptibility, \chi=\frac{\mathrm{I}}{\mathrm{H}} where, I= Magnetic moment  Volume =20×10−610−6=20 N/m2\mathrm{I}=\frac{\text{ Magnetic moment }}{\text{ Volume }}=\frac{20 \times 10^{-6}}{10^{-6}}=20 \mathrm{~N} / \mathrm{m}^{2} Now , χ=2060×103=13×10−3=3.3×10−4\chi=\frac{20}{60 \times 10^{3}}=\frac{1}{3} \times 10^{-3}=3.3 \times 10^{-4}
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