A magnet of total magnetic moment 10 - 2 i ^ A m 2 is placed in a time varying magnetic field, B i ^ cos ω t where B = 1 Tesla and ω = 0.125 rad s - 1 . The work done for reversing the direction of the magnetic moment at t = 1 second, is:

Step-by-step solution

As we know that, work done in rotating a magnetic dipole in magnetic field is, W = M B ( cos θ 1 - cos θ 2 )         . . . ( 1 ) Now in the above given question we have, Magnetic Moment ( M ) = 10 - 2   i ^   A   m 2 ,Magnetic Field = B i ^ cos ω t with B = 1   T , ω = 0 . 125   rad   s - 1 and t = 1   s Let initial angle ( θ 1 ) = 0 ∘ so on reversing the direction of magnetic moment final angle ( θ 2 ) = 180 ∘ Now, sub