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JEE Main 2003
Exam
JEE Main
Year
2003
Subject
Physics
Chapter
Magnetic Properties of Matter

JEE Main 2003 · Physics · Magnetic Properties of Matter

A magnetic needle lying parallel to a magnetic field requires W...

A magnetic needle lying parallel to a magnetic field requires W\mathrm{W} units of work to turn it through 60∘60^{\circ}. The torque needed to maintain the needle in this position will be

Options

  1. A3 W\sqrt{3} \mathrm{~W}
  2. BW
  3. C32 W\frac{\sqrt{3}}{2} \mathrm{~W}
  4. D2 W2 \mathrm{~W}

Correct answer

A. 3 W\sqrt{3} \mathrm{~W}

Step-by-step solution

τ=(H)tan⁡60∘=W⋅3\tau=(\mathrm{H}) \tan 60^{\circ} \quad=\mathrm{W} \cdot \sqrt{3}
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