JEE Main202621 January 2026Morning ShiftPhysicsMathematics in PhysicsActual
In an experiment the values of two spring constants were measured as k₁=(10 0.2) N / m and k₂=(20 0.3) N / m . If these springs are connected in parallel, then the percentage error in equivalent spring constant is :
Options
- A1.33%
- B1.67%
- C2.67%
- D2.33%
Correct answer
B. 1.67%
Step-by-step solution
For parallel combination: k_ eq = k₁ + k₂ = 10 + 20 = 30 N/m For sum, absolute errors add: k_ eq = k₁ + k₂ = 0.2 + 0.3 = 0.5 N/m Percentage error = k_ eq k_ eq 100 = 0.5 30 100 = 1.67 %