7 . 8 g of a compound having molecular formula C 6 H 6 , on reacting with CH 3 COCl / AlCl 3 gives 8 . 4 g of a product which has molecular formula C 8 H 8 O . Calculate the percentage yield of the product C 8 H 8 O . (Given atomic weights of H , C and O respectively are 1 , 12 and 16 )

Step-by-step solution

Molar mass of benzene = 78   g / mol Mole of benzene = Given   mass Molar   mass = 7 . 8 78 = 0 . 1   mol C 6 H 6   +   CH 3 COCl / AlCl 3 → C 8 H 8 O By applying the mole-mole analysis, one mole of benzene gives the one mole of C 8 H 8 O . So, 0 . 1   mol of benzene gives the 0 . 1   mol of C 8 H 8 O . Molar mass of C 8 H 8 O = 120   g / mol Mass of C 8 H 8 O formed = mole × molar   mass = 0 . 1 × 120 = 12 g Percentage yield = Experimental   yi