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AP EAMCET202021 Sep 2020Morning ShiftChemistryHydrocarbonsActual

1-chloro butane on treatment with alcoholic potash forms

Options

  1. A2-butanol
  2. B1-butene
  3. C1-butanol
  4. D2-butene

Correct answer

B. 1-butene

Step-by-step solution

Alc. ( KOH ) is a dehydrohalogenation agent, it reacts with an alkyl halide and alkene forms as a product. Reaction of process can be given by ( 1-chlorobutane CH ₃ CH ₂ CH ₂ CH ₂ Cl Alc , KOH 1-butene CH ₃ CH ₂ CH = CH ₂ ) Hence, option (b) is correct.

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