The velocity ( v ) versus time ( t ) plot of a particle is shown in the figure, for a time interval of 40 s . The total distance travelled by the particle and the average velocity during this period are, respectively _______.

Step-by-step solution

The total distance travelled by the particle is equal to the sum of the magnitudes of the areas under the velocity-time graph. Area of the first triangle (from t = 0 to t = 20 s ) is: A₁ = 1 2 20 5 = 50 m Magnitude of the area of the second triangle (from t = 20 to t = 40 s ) is: |A₂| = | 1 2 20 (-5) | = 50 m Total distance = A₁ + |A₂| = 50 + 50 = 100 m The total displacement is the algebraic sum of the areas under the velocity-time graph. Total displacement = A₁ + A₂ = 50 - 50 = 0 m Average velocity is the ratio o