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JEE Main20268 April 2026Evening ShiftPhysicsMotion in Two DimensionsActual

A car moving with a speed of 54 km/h takes a turn of radius 20 m. A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take g=10 m/s ^2 )

Options

  1. A⁻¹(0.5)
  2. B⁻¹(0.75)
  3. C⁻¹(1.125)
  4. D⁻¹(0.25)

Correct answer

C. ⁻¹(1.125)

Step-by-step solution

Speed of the car, v = 54 5 18 = 15 m/s. In the frame of the car, the pendulum bob experiences a pseudo force (centrifugal force) horizontally outwards and the gravitational force downwards. Let T be the tension in the string and be the angle it makes with the vertical. For equilibrium in the car's frame, the horizontal and vertical forces balance: T = mv^2 r T = mg Dividing the two equations, we get: = v^2 rg Substituting the given values v = 15 m/s, r = 20 m, and g = 10 m/s ^2 : = (15)^2 20 10 = 225 200 = 1.125 =

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