The average energy released per fission for the nucleus of ₉₂²³⁵ U is 190 MeV. When all the atoms of 47 g pure ₉₂²³⁵ U undergo fission process, the energy released is 10²³ MeV . The value of is _ _ _ _ . (Avogadro Number =6 10²³ per mole)

Step-by-step solution

The number of ²³⁵ U atoms in 47 g is determined using Avogadro's number. Molar mass of ²³⁵ U is 235 g/mol, so the number of moles is n = 47/235 mol. The total number of atoms is N = (47/235) 6 10²³ . Since each fission releases 190 MeV, the total energy released is: E_ total = N 190 = 47 6 10²³ 235 190 = 47 6 190 235 10²³ MeV. Calculating the numerator: 47 6 190 = 282 190 = 53580 . Therefore: E_ total = 53580 235 10²³ = 228 10²³ MeV, giving = 228 .