JEE Main20252 Apr 2025Evening ShiftPhysicsNuclear PhysicsActual
Energy released when two deuterons ( ₁ H ^2 ) fuse to form a helium nucleus ( ₂ He ^4 ) is : (Given : Binding energy per nucleon of ₁ H ^2=1.1 MeV and binding energy per nucleon of ₂ He ^4=7.0 MeV )
Options
- A8.1 MeV
- B5.9 MeV
- C23.6 MeV
- D26.8 MeV
Correct answer
C. 23.6 MeV
Step-by-step solution
aligned & E_B= BE _ reactant - BE _ product & =1.1 2+1.1 2-7 4=-23.6 MeV & = Q =23.6 MeV aligned