JEE Main20249 Apr 2024Evening ShiftPhysicsNuclear PhysicsActual
The energy released in the fusion of 2 ~kg of hydrogen deep in the sun is E_H and the energy released in the fission of 2 ~kg of ²³⁵ U is E_U . The ratio E_H E_U is approximately: (Consider the fusion reaction as 4 H+2 e ⁻ ₂^4 He +2 v+6 +26.7 MeV , energy released in the fission reaction of ²³⁵ U is 200 MeV per fission nucleus and N _ A = .6.023 10²³ )
Options
- A7.62
- B25.6
- C15.04
- D9.13
Correct answer
A. 7.62
Step-by-step solution
In each fusion reaction, 4 ₁^1 H nucleus are used. Energy released per Nuclei of ₁^1 H = 26.7 4 MeV Energy released by 2 ~kg hydrogen ( E _ H )= 2000 1 N _ A 26.7 4 MeV & aligned & Energy released by 2 ~kg Vranium ( E _ V ) & = 2000 235 N _ A 200 MeV aligned So, E_H E_V =235 26.7 4 200 =7.84 Approximately close to 7.62