The radius of a nucleus of mass number 64 is 4 . 8 fermi. Then the...

Radius of a nucleus is given by, $R = {R}_{0}{A}^{1 / 3}$.

Therefore, ${R}^{3} ∝ A$

$⇒ {\left(\dfrac{4 . 8}{4}\right)}^{3} = \dfrac{64}{A}$

$⇒ \dfrac{64}{A} = ( 1 . 2{)}^{3}$

$⇒ \dfrac{64}{A} = 1 . 44 \times 1 . 2$

$⇒ A = \dfrac{64}{1 . 44 \times 1 . 2} = \dfrac{1000}{x}$

$⇒ x = \dfrac{144 \times 12}{64} = 27$