A nucleus with mass number 242 and binding energy per nucleon as 7 . 6   MeV breaks into two fragment each with mass number 121 . If each fragment nucleus has binding energy per nucleon as 8 . 1   MeV , the total gain in binding e

Question

A nucleus with mass number 242 and binding energy per nucleon as 7 . 6 &#160; MeV breaks into two fragment each with mass number 121 . If each fragment nucleus has binding energy per nucleon as 8 . 1 &#160; MeV , the total gain in binding energy is _ _ _ _ _ _ _ &#160; MeV .

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Correct answer: 121

Binding energy is given by E = &#8710; m c 2 where &#8710; m is the mass defect. The energy per nucleon of the nucleus having mass number 242 is 7 . 6 &#160; MeV . The initial binding energy is, B E = 242 &#215; 7 . 6 &#160; MeV The energy per nucleon of the nucleus with mass number 121 is 8 . 1 &#160; MeV . Therefore, binding energy is B E ' = 2 121 &#215; 8 . 1 &#160; MeV The gain in the binding energy is B E ' - B E &#160; = &#160; ( 8 . 1 &#160; &#8211; &#160; 7 . 6 ) &#160; &#215; &#160; 242 &#160; MeV

A nucleus with mass number 242 and binding energy per nucleon as 7 . 6   MeV breaks into two fragment each with mass number 121 . If each fragment nucleus has binding energy per nucleon as 8 . 1   MeV , the total gain in binding energy is _ _ _ _ _ _ _   MeV .

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More from Nuclear Physics

A nucleus with mass number 242 and binding energy per nucleon as 7 . 6 &#160; MeV breaks into two fragment each with mass number 121 . If each fragment nucleus has binding energy per nucleon as 8 . 1 &#160; MeV , the total gain in binding energy is _ _ _ _ _ _ _ &#160; MeV .

Correct answer

Step-by-step solution

More from Nuclear Physics

A nucleus with mass number 242 and binding energy per nucleon as 7 . 6 MeV breaks into two fragment each with mass number 121 . If each fragment nucleus has binding energy per nucleon as 8 . 1 MeV , the total gain in binding energy is _ _ _ _ _ _ _ MeV .