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JEE Main 202330 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
30 January
Shift
Evening Shift
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2023 · 30 January · Evening Shift · Physics · Nuclear Physics

Given below are two statements : one is labelled as Assertion A and...

Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R

Assertion A : The nuclear density of nuclides B510,L36i,F2656e,N1020eandB83209iB 510 , L 36 i, F 2656 e, N 1020 e\text{and} B 83209 i can be arranged as ρBiN>ρFeN>ρNeN>ρBN>ρLiN{ρ}_{Bi}^{N} > {ρ}_{Fe}^{N} > {ρ}_{Ne}^{N} > {ρ}_{B}^{N} > {ρ}_{Li}^{N}

Reason R : The radius RR of nucleus is related to its mass number AA as R=R0A13R = {R}_{0}A\dfrac{1}{3}, where R0{R}_{0} is a constant.

In the light of the above statement, choose the correct answer from the options given below :

Options

  1. ABoth A and R are true and R is the correct explanation of A
  2. BA is false but R is true
  3. CA is true but R is false
  4. DBoth A and R are true but R is NOT the correct explanation of A

Correct answer

B. A is false but R is true

Step-by-step solution

Nuclear density is given by, ρ=m43π(R0)3ρ = \dfrac{m}{\dfrac{4}{3}\pi{\left({R}_{0}\right)}^{3}}, where mm is mass of proton. Clearly it is independent of AA and same for all nucleus.

Radius of the nucleus is given by, R=R0A13R = {R}_{0}A\dfrac{1}{3}.

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