The energy released per fission of nucleus of X 240 is 200MeV . The...

The energy released per fission of nucleus of $X 240$ is $200MeV$ . The energy released if all the atoms in $120g$ of pure $X 240$ undergo fission is _____ $\times {10}^{25}MeV$ .

(Given ${N}_{A} = 6 \times {10}^{23}$ )

Correct answer

Step-by-step solution

Energy released per fission is $200MeV$ .

The number of atoms $n$ in $120g$ :

$n = \dfrac{120}{240} \times 6 \times {10}^{23}\text{atoms} .$

Total energy released, $E = n \times 200 \times {10}^{6}$

$= 6 \times {10}^{25}MeV$

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