Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:
$X 12 + X 12 = Y 24$
The binding energies per nucleon $X 12$ and $Y 24$ are $1 . 1MeV$ and $7 . 6MeV$ respectively. The energy released in this process is_____ $MeV$ .

Question

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:

$X 12 + X 12 = Y 24$

The binding energies per nucleon $X 12$ and $Y 24$ are $1 . 1MeV$ and $7 . 6MeV$ respectively. The energy released in this process is_____ $MeV$ .

Quantrex Academy · Accepted Answer

Correct answer: 0

Energy released in the given process = Binding energy of product - Binding energy of reactants. = 7 . 6 × 4 - (1 . 1 × 2) × 2 = 30 . 4 - 4 . 4 = 26MeV

Two lighter nuclei combine to form a comparatively heavier nucleus...

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