JEE Main202226 Jul 2022Evening ShiftPhysicsNuclear PhysicsActual
Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: X 1 2 + X 1 2 = Y 2 4 The binding energies per nucleon X 1 2 and Y 2 4 are 1 . 1 MeV and 7 . 6 MeV respectively. The energy released in this process is_____ MeV .
Correct answer
0
Step-by-step solution
Energy released in the given process = Binding energy of product - Binding energy of reactants. = 7 . 6 × 4 - 1 . 1 × 2 × 2 = 30 . 4 - 4 . 4 = 26 MeV