In the following nuclear reaction, D α → D _ 1 β ^ - → D _ 2 α → D _ 3 γ → D _ 4 Mass number of D is 182 and atomic number is 74 . Mass number and atomic number of D _ 4 respectively will be

Correct answer: A. 174 and 71 Equivalent reaction can be written as D → D _ 4 + 2α + β ^ - + γ So, mass number of D _ 4 = mass number of D - 2 × 4 = 182 - 8 = 174 Atomic number of D _ 4 = atomic number of D - 2 × 2 + 1 = 74 - 4 + 1 = 71 The reaction is D 74182 ⟶ _ α D1 72178 ⟶ _ β ^ - D2 73178 ⟶ _ α D3 71174 → _ γ D4 71174

JEE Main 202229 JuneEvening Shift

Exam: JEE Main
Year: 2022
Date: 29 June
Shift: Evening Shift
Subject: Physics
Chapter: Nuclear Physics

JEE Main 2022 · 29 June · Evening Shift · Physics · Nuclear Physics

In the following nuclear reaction, D α → D _ 1 β ^ - → D _ 2 α → D...

In the following nuclear reaction,

D\overset{\alpha}{\to}{D}_{1}\overset{{\beta}^{-}}{\to}{D}_{2}\overset{\alpha}{\to}{D}_{3}\overset{\gamma}{\to}{D}_{4}

Mass number of

D

182

and atomic number is

74

. Mass number and atomic number of

{D}_{4}

respectively will be

Options

A $174$ and $71$
B $174$ and $69$
C $172$ and $69$
D $172$ and $71$

Correct answer

A. $174$ and $71$

Step-by-step solution

Equivalent reaction can be written as $D \to {D}_{4} + 2\alpha + {\beta}^{-} + \gamma$

So, mass number of ${D}_{4} =$ mass number of $D - 2 \times 4 = 182 - 8 = 174$

Atomic number of ${D}_{4} =$ atomic number of $D - 2 \times 2 + 1 = 74 - 4 + 1 = 71$

The reaction is

$D 74182 \mathop{⟶}_{\alpha} D1 72178 \mathop{⟶}_{{\beta}^{-}} D2 73178 \mathop{⟶}_{\alpha} D3 71174 \mathop{\to}_{\gamma} D4 71174$

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