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How many alpha and beta particles are emitted when Uranium U 92 238 decays to lead Pb 82 206 ?

Options

  1. A3 alpha particles and 5 beta particles
  2. B6 alpha particles and 4 beta particles
  3. C4 alpha particles and 5 beta particles
  4. D8 alpha particles and 6 beta particles

Correct answer

D. 8 alpha particles and 6 beta particles

Step-by-step solution

U 92 238 → Pb 82 206 Change in mass number is 4 α = 238 - 206 = 32 ⇒ α = 8 Change in atomic number is - 2 α + β = - 10 ⇒ - 16 + β = - 10 ⇒ β = 6

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