From the given data, the amount of energy required to break the nucleus of aluminium $Al 1327$ is __________ $x \times {10}^{- 3}J$
Mass of neutron $= 1 . 00866u$
Mass of proton $= 1 . 00726u$
Mass of Aluminium nucleus $= 27 . 18846u$
(Assume $1u$ corresponds to $xJ$ of energy)
(Round off to the nearest integer)

Question

From the given data, the amount of energy required to break the nucleus of aluminium $Al 1327$ is __________ $x \times {10}^{- 3}J$

Mass of neutron $= 1 . 00866u$
Mass of proton $= 1 . 00726u$
Mass of Aluminium nucleus $= 27 . 18846u$
(Assume $1u$ corresponds to $xJ$ of energy)
(Round off to the nearest integer)

Quantrex Academy · Accepted Answer

Correct answer: 0

= (Z m _ P + ( A - Z ) m _ n ) - M _ Al = ( 13 × 1 . 00726 + 14 × 1 . 00866 ) - 27 . 18846 = 27 . 21562 - 27 . 18846 = 0 . 02716u E = 27 . 16x × 10 ^ - 3 J

From the given data, the amount of energy required to break the...

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