The half-life of Au 198 is 2 . 7 days. The activity of 1 . 50 mg of Au 198 , if its atomic weight is 198 g mol - 1 is, N A = 6 × 10 23 mol - 1

Step-by-step solution

The activity will be A = λ N Now, λ = ln 2 t 1 2 and N = 1 . 5 × 10 - 3 198 × 6 × 10 23 Therefore, activity in Ci , A = ln 2 t 1 2 × 1 . 5 × 10 - 3 198 × 6 × 10 23 3 . 7 × 10 - 10 = ln 2 2 . 7 × 24 × 60 × 60 × 1 . 5 × 10 - 3 198 × 6 × 10 23 3 . 7 × 10 - 10 = 366   Ci ≈ 357   Ci