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You are given that Li 3 7 = 7 . 0160 u , Mass of Mass of He 2 4 = 4 . 0026 u and Mass of He 1 1 = 1 . 0079 H When 20 g of Li 3 7 is converted into 2 4 He by proton capture, the energy liberated, (in kWh ), is : [Mass of nucleon = 1 GeV / c 2 ]

Options

  1. A4 . 5 × 10 5
  2. B8 × 10 6
  3. C6 . 82 × 10 5
  4. D1 . 33 × 10 6

Correct answer

D. 1 . 33 × 10 6

Step-by-step solution

E = Δ m C 2 E = ( 1 . 0079 + 7 . 0160 - 2 ( 4 . 0026 ) × 931 = 1 . 33 × 10 6

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