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JEE Main 20206 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Morning Shift
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2020 · 6 September · Morning Shift · Physics · Nuclear Physics

You are given that Li 37 = 7 . 0160u, Mass of Mass of He 24 = 4 ....

You are given that Li37=7.0160u,Li 37 = 7 . 0160u,Mass of Mass of He24=4.0026uHe 24 = 4 . 0026u and Mass of He11=1.0079HHe 11 = 1 . 0079H When 20g20g of Li37Li 37 is converted into 24{}_{2}^{4} He by proton capture, the energy liberated, (in kWhkWh ), is : [Mass of nucleon =1GeV/c2= 1GeV / {c}^{2}]

Options

  1. A4.5×1054 . 5 \times {10}^{5}
  2. B8×1068 \times {10}^{6}
  3. C6.82×1056 . 82 \times {10}^{5}
  4. D1.33×1061 . 33 \times {10}^{6}

Correct answer

D. 1.33×1061 . 33 \times {10}^{6}

Step-by-step solution

E=\DeltamC2E = \Deltam{C}^{2}

E=(1.0079+7.0160−2(4.0026)×931E = ( 1 . 0079 + 7 . 0160 - 2 ( 4 . 0026 ) \times 931

=1.33×106= 1 . 33 \times {10}^{6}

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