Two deuterons undergo nuclear fusion to form a Helium nucleus. The...

Q = ∑ B . E . ofproducts - ∑ B . E . ofreactants$<br /><br />The equation for two deuterons combining to form Helium nucleus is given as${H}^{2}{+}_{1}{H}^{2}{\to}_{2}{H}^{4}$<br /><br />Energyreleased = Q = 4\left[B . E . \left({}_{2}{H}^{4}\right)\right] - 4\left[B . E . \left({}_{1}{H}^{2}\right)\right]$
$= 4 \times 7 - 4 \times \text{1.1}$

$= 28 - \text{4.4}$

The energy released in this process is $= \text{23.6}MeV$