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A radioactive nucleus (initial mass number A and atomic number Z) emits 3 -particles and 2 positrons. The ratio of number of neutrons to that of protons in the final nucleus will be

Options

  1. AA-Z-8 Z-4
  2. BA-Z-4 Z-8
  3. CA-Z-12 Z-4
  4. DA-Z-4 Z-2

Correct answer

B. A-Z-4 Z-8

Step-by-step solution

In positive beta decay a proton is transformed into a neutron and a positron is emitted. p ⁺ n ^0+ e ⁺ no. of neutrons initially was A-Z no. of neutrons after decay (A-Z)-3 2 (due to alpha particles) +2 1 (due to positive beta decay) The no. of proton will reduce by 8 . [as 3 2 (due to alpha particles) +2 (due to positive beta decay)] Hence atomic number reduces by 8 .

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