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If the binding energy per nucleon in ₃^7 Li and ₂^4 He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction p + ₃^7 Li 2 ₂^4 He energy of proton must be

Options

  1. A39.2 MeV
  2. B28.24 MeV
  3. C17.28 MeV
  4. D1.46 MeV

Correct answer

C. 17.28 MeV

Step-by-step solution

=(8 7.06-7 5.60) MeV =17.28 MeV

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