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JEE Main 2006
Exam
JEE Main
Year
2006
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2006 · Physics · Nuclear Physics

If the binding energy per nucleon in _3^7 Li and _2^4 He nuclei are...

If the binding energy per nucleon in 37Li{ }_3^7 \mathrm{Li} and 24He{ }_2^4 \mathrm{He} nuclei are 5.60MeV5.60 \mathrm{MeV} and 7.06MeV7.06 \mathrm{MeV} respectively, then in the reaction p+37Li→224He\mathrm{p}+{ }_3^7 \mathrm{Li} \rightarrow 2{ }_2^4 \mathrm{He} energy of proton must be

Options

  1. A39.2MeV39.2 \mathrm{MeV}
  2. B28.24MeV28.24 \mathrm{MeV}
  3. C17.28MeV17.28 \mathrm{MeV}
  4. D1.46MeV1.46 \mathrm{MeV}

Correct answer

C. 17.28MeV17.28 \mathrm{MeV}

Step-by-step solution

=(8×7.06−7×5.60)MeV=17.28MeV=(8 \times 7.06-7 \times 5.60) \mathrm{MeV}=17.28 \mathrm{MeV}
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