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The binding energy per nucleon of deuteron ( ₁^2 H ) and helium nucleus ( ₂^4 He ) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Options

  1. A13.9 MeV
  2. B26.9 MeV
  3. C23.6 MeV
  4. D19.2 MeV

Correct answer

C. 23.6 MeV

Step-by-step solution

Energy released = total binding energy of product - total binding energy of reactants 28-(2 2.2)=28-4.4=236 MeV

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