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JEE Main 2003
Exam
JEE Main
Year
2003
Subject
Physics
Chapter
Nuclear Physics

JEE Main 2003 · Physics · Nuclear Physics

When a U^ 238 nucleus originally at rest, decays by emitting an...

When a U238U^{238} nucleus originally at rest, decays by emitting an alpha particle having a speed ' uu ', the recoil speed of the residual nucleus is

Options

  1. A4u238\frac{4 \mathrm{u}}{238}
  2. B−4u234-\frac{4 \mathrm{u}}{234}
  3. C4u234\frac{4 \mathrm{u}}{234}
  4. D−4u238-\frac{4 \mathrm{u}}{238}

Correct answer

A. 4u238\frac{4 \mathrm{u}}{238}

Step-by-step solution

Applying the principle of conservation of linear momentum (4) (u)=(v)(238)⇒v=4u238(\mathrm{u})=(\mathrm{v})(238) \Rightarrow \mathrm{v}=\frac{4 \mathrm{u}}{238}
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