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A nucleus with Z =92 emits the following in a sequence: , ⁻, ⁻ , , , , , ⁻, ⁻, , ⁺, ⁺, . Then Z of the resulting nucleus is

Options

  1. A76
  2. B78
  3. C82
  4. D74

Correct answer

B. 78

Step-by-step solution

No. of particles emitted =8, No. of ⁻ particles emitted =4, No.of ⁺ particles emitted =2z=92-2 8+4-2=78

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