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AP EAMCET201920 Apr 2019Evening ShiftChemistryHydrogenActual

Identify the correct statements from the following I. B ₂ H ₆ is an electron deficient hydride. II. NH ₃ an electron rich hydride. III. NaH is a covalent hydride. IV. YbH ₂₅₅ is an interstitial hydride.

Options

  1. AI, II, III
  2. BII, III, IV
  3. CI, II, IV
  4. DI, III, IV

Correct answer

C. I, II, IV

Step-by-step solution

(I) B ₂ H ₆ (diborane) is an electron deficient hydride. This can be explained on the basis of structure given below. 3 C -2 e⁻ electron deficient bridge bond (II) NH ₃ is electron rich hydride due to presence of lone pair of electrons. (III) NaH is an ionic hydride, generally hydride of alkali metals are ionic. Hence, statement III is incorrect. (IV) YbH _ 2.55 is an interstitial hydride. Here, smaller atom like hydrogen present in interstitial space of Yb metal. Hence, it forms interstitial hydride. Thus, option

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