How many millilitres of 20 volume H ₂ O ₂ solution is needed to react completely with 500 ~mL of acidified 1 ~N KMnO ₄ , solution?

Step-by-step solution

Given, Normality of KMnO ₄ (N₁ )=1 ~N Volume of KMnO ₄ (V₁ )=500 ~mL Normality of H ₂ O ₂ (N₂ )= Volume strength 5.6( eq. mass ) = 20 5.6 (N₂ )=3.5 Now, N₁ V₁ ( KMnO ₄ )=N₂ V₂ ( H ₂ O ₂ ) aligned & 1 500=3.57 V₂ & V₂= 500 a-0 =140 ~mL aligned