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JEE Main 20262 AprilEvening Shift
Exam
JEE Main
Year
2026
Date
2 April
Shift
Evening Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2026 · 2 April · Evening Shift · Physics · Semiconductors

If X and Y are the inputs, the given circuit works as _______.

If XX and YY are the inputs, the given circuit works as _______.
If X and Y are the inputs, the given circuit works as _______.

Options

  1. AOR gate
  2. BAND gate
  3. CNAND gate
  4. DNOR gate

Correct answer

D. NOR gate

Step-by-step solution

The circuit consists of four NAND gates.

The first two NAND gates have their inputs tied together, acting as NOT gates. Their outputs are X‾\overline{X} and Y‾\overline{Y}.

These outputs are fed into the third NAND gate. The output of this gate is:
y′=X‾⋅Y‾‾y' = \overline{\overline{X} \cdot \overline{Y}}

Using De Morgan's theorem:
y′=X‾‾+Y‾‾=X+Yy' = \overline{\overline{X}} + \overline{\overline{Y}} = X + Y

This output is fed into the fourth NAND gate, which also has its inputs tied together, acting as a NOT gate. The final output is:
Output =X+Y‾= \overline{X + Y}

This represents the Boolean expression for a NOR gate.

Answer: NOR gate
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