JEE Main 20257 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2025
- Date
- 7 April
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Semiconductors
JEE Main 2025 · 7 April · Evening Shift · Physics · Semiconductors
Consider the following logic circuit. The output is Y=0 when :
Consider the following logic circuit.

The output is when :
The output is when :
Options
- A and
- B and
- C and
- D and
Correct answer
A. and
Step-by-step solution
\begin{aligned}& \mathrm{Y}_1=\mathrm{A} \cdot \mathrm{ B}, \mathrm{Y}_2=\overline{\mathrm{A}}+\mathrm{B} \\
& \mathrm{Y}=\overline{\mathrm{Y}_1 \cdot \mathrm{Y}_2}=\overline{\mathrm{Y}_1+\overline{\mathrm{Y}_2 \\
& \mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{ B}}+\overline{\mathrm{A}+\mathrm{B}} \\
& \mathrm{Y}=\overline{\mathrm{A}}+\overline{\mathrm{B}}+\mathrm{A} \cdot \overline{\mathrm{ B}}\end{aligned}$