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JEE Main20246 Apr 2024Evening ShiftPhysicsSemiconductorsActual

The acceptor level of a p-type semiconductor is 6 eV . The maximum wavelength of light which can create a hole would be : Given hc =1242 eV nm .

Options

  1. A414 ~nm
  2. B103.5 ~nm
  3. C207 ~nm
  4. D407 ~nm

Correct answer

C. 207 ~nm

Step-by-step solution

aligned & Energy = hc & E = 1240 ( nm ) eV & 6= 1240 ( nm ) & = 1240 6 =207 ~nm aligned

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