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JEE Main20241 Feb 2024Morning ShiftPhysicsSemiconductorsActual

In the given circuit if the power rating of Zener diode is 10 mW , the value of series resistance R s to regulate the input unregulated supply is:

Options

  1. A3 7 k Ω
  2. B10 Ω
  3. C1 k Ω
  4. D10 k Ω

Correct answer

A. 3 7 k Ω

Step-by-step solution

Potential drop across R s , V 1 = 8 - 5 = 3 V Current through the load resistor I = 5 1 × 10 3 = 5 mA Maximum current through Zener diode I Z , max = 10 5 = 2 mA And minimum current through Zener diode I Z , min = 0 ∴ I S , max = 5 + 2 = 7 m A And R S , min = V 1 I S , max = 3 7 k Ω Similarly, I S , min = 5 mA And R S , max = V 1 I S , min = 3 5 k Ω ∴ 3 7 k Ω < R s < 3 5 k Ω

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