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JEE Main 202313 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
13 April
Shift
Morning Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2023 · 13 April · Morning Shift · Physics · Semiconductors

For the following circuit and given inputs A and B, choose the...

For the following circuit and given inputs AA and B,B, choose the correct option for output ‘Y’‘ Y ’

For the following circuit and given inputs A and B, choose the correct option for output ‘ Y ’

For the following circuit and given inputs A and B, choose the correct option for output ‘ Y ’

Options

  1. AA heavy string is fastened at one end to a movable support and at the other end to a light thread, as shown in the
  2. BA heavy string is fastened at one end to a movable support and at the other end to a light thread, as shown in the
  3. CA heavy string is fastened at one end to a movable support and at the other end to a light thread, as shown in the
  4. DA heavy string is fastened at one end to a movable support and at the other end to a light thread, as shown in the

Correct answer

A. A heavy string is fastened at one end to a movable support and at the other end to a light thread, as shown in the

Step-by-step solution

The signal AA is given to a NOR gate and BB is given to an OR gate. The output of these two signals is given to a NAND gate. Using the laws of Boolean algebra,

Y=A⋅B¯=A+B¯Y = \overset{¯}{A \cdot B} = A + \overset{¯}{B}.

Analysing from the input graphs, one can see,

t1−t2:A=0,B¯=0,Y=0t2−t3:A=1,B¯=0,Y=1t3−t4:A=0,B¯=1,Y=1t4−t5:A=1,B¯=0,Y=1t5−t6:A=1,B¯=1,Y=1{t}_{1} - {t}_{2}: A = 0, \overset{¯}{B} = 0, Y = 0{t}_{2} - {t}_{3}: A = 1, \overset{¯}{B} = 0, Y = 1{t}_{3} - {t}_{4}: A = 0, \overset{¯}{B} = 1, Y = 1{t}_{4} - {t}_{5}: A = 1, \overset{¯}{B} = 0, Y = 1{t}_{5} - {t}_{6}: A = 1, \overset{¯}{B} = 1, Y = 1

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