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JEE Main 202229 JulyMorning Shift
Exam
JEE Main
Year
2022
Date
29 July
Shift
Morning Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2022 · 29 July · Morning Shift · Physics · Semiconductors

If the potential barrier across a p - n junction is 0 . 6V . Then...

If the potential barrier across a p−np - n junction is 0.6V0 . 6V. Then the electric field intensity, in the depletion region having the width of 6×10−6m6 \times {10}^{- 6}m, will be _____ ×105NC−1\times {10}^{5}N{C}^{- 1}If the potential barrier across a p - n junction is 0 . 6V . Then the electric field intensity, in the depletion region

Correct answer

0

Step-by-step solution

If the potential barrier across a p - n junction is 0 . 6V . Then the electric field intensity, in the depletion region

Electric field intensity is E=Vd=PotentialbarrieracrossjunctionwidthofdepletionregionE = \dfrac{V}{d} = \dfrac{Potentialbarrieracrossjunction}{widthofdepletionregion}

=0.6V6×10−6m=1×105Vm−1= \dfrac{0 . 6V}{6 \times {10}^{- 6}m} = 1 \times {10}^{5}V{m}^{- 1}

=1×105NC−1= 1 \times {10}^{5}N{C}^{- 1}

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