Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202229 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
29 June
Shift
Morning Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2022 · 29 June · Morning Shift · Physics · Semiconductors

A transistor is used in an amplifier circuit in common emitter...

A transistor is used in an amplifier circuit in common emitter mode. If the base current changes by 100\muA100\muA, it brings a change of 10mA10mA in collector current. If the load resistance is 2kΩ2kΩ and input resistance is 1kΩ1kΩ, the value of power gain is x×104x \times {10}^{4}. The value of xx is _____ .

Correct answer

0

Step-by-step solution

βAC=ΔiCΔiB=10×10−3100×10−6=100{\beta}_{AC} = \dfrac{\Delta{i}_{C}}{\Delta{i}_{B}} = \dfrac{10 \times {10}^{- 3}}{100 \times {10}^{- 6}} = 100

Power gain,AP=∆iC2Rout∆iB2Rin=βAC2RoutRin=(100)2×2×103103=2×104{A}_{P} = \dfrac{∆ {{i}_{C}}^{2}{R}_{out}}{∆ {{i}_{B}}^{2}{R}_{in}} = {\beta}_{AC}^{2}\dfrac{{R}_{out}}{{R}_{in}} = {\left(100\right)}^{2} \times \dfrac{2 \times {10}^{3}}{{10}^{3}} = 2 \times {10}^{4}

Therefore, x=2x = 2

Practice Semiconductors on Quantrex Academy →

More from Semiconductors

The output Y for the given inputs A and B to the circuit is: JEE Main 2026Refer to the logic circuit given below. For two inputs (A=1, B=1) and (A=0, B=1) , output… JEE Main 2026The maximum rated power of the LED is 2 mW and it is used in the circuit with input… JEE Main 2026In a semiconductor p-n diode, the doping concentrations on p-side and n-side are 10^ 15… JEE Main 2026For the given logic circuit, which of the following inputs combination will make both LED… JEE Main 2026Given below are two statements: one is labelled as Assertion A and the other is labelled… JEE Main 2026A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the… JEE Main 2026Two 4 bits binary numbers, A = 1101 and B = 1010 are given in the inputs of a logic… JEE Main 2026 Full Semiconductors list All JEE Main PYQs