In the following circuit, the correct relation between output (Y)...

In the following circuit, the correct relation between output $\left(Y\right)$ and inputs $A and B$ will be

In the following circuit, the correct relation between output (Y) and inputs A and B will be

Options

A $Y = A \cdot B$
B $Y = A + B$
C $Y = A \cdot B$
D $Y = A + B$

Correct answer

C. $Y = A \cdot B$

Step-by-step solution

When both of the inputs are given with $+ 10V$ that is logical $1$ , both of the diodes are in OFF condition and hence supply voltage will appear at the base terminal of the transistor which makes it switched ON and supply voltage gets a path to the ground through this transistors. Therefore, it represents NAND gate.

Hence, $Y = A \cdot B$

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