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JEE Main202227 Jun 2022Evening ShiftPhysicsSemiconductorsActual

The cut-off voltage of the diodes (shown in figure) in forward bias is 0 . 6 V . The current through the resister of 40 Ω is _____ mA .

Correct answer

0

Step-by-step solution

Here diode D 1 is forward biased and diode D 2 is reverse biased. So, no current will flow through diode D 2 resistor. Current through the resistor of 40   Ω is i = 1 - 0 . 6 60 + 40 = 0 . 4 100 = 4   mA

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