In an experiment of CE configuration of n - p - n transistor, the transfer characteristics are observed as given in figure. If the input resistance is 200Ω and output resistance is 60Ω , the voltage gain in this

Correct answer: 0 Voltage gain, A _ V = ? Input Resistance = 200Ω Output Resistance = 60Ω β = Δ I _ C Δ I _ B = (5 - 0) × 10 ^ - 3 (100 - 0) × 10 ^ - 6 = 50 A _ V = β R _ C R _ B = 50 × (60)/(200) = 15

JEE Main 202225 JuneEvening Shift

Exam: JEE Main
Year: 2022
Date: 25 June
Shift: Evening Shift
Subject: Physics
Chapter: Semiconductors

JEE Main 2022 · 25 June · Evening Shift · Physics · Semiconductors

In an experiment of CE configuration of n - p - n transistor, the...

In an experiment of $CE$ configuration of $n - p - n$ transistor, the transfer characteristics are observed as given in figure.

In an experiment of CE configuration of n - p - n transistor, the transfer characteristics are observed as given in

If the input resistance is $200Ω$ and output resistance is $60Ω$ , the voltage gain in this experiment will be _____ .

Correct answer

Step-by-step solution

In an experiment of CE configuration of n - p - n transistor, the transfer characteristics are observed as given in

Voltage gain, ${A}_{V} = ?$
Input Resistance $= 200Ω$
Output Resistance $= 60Ω$

$\beta = \dfrac{\Delta{I}_{C}}{\Delta{I}_{B}} = \dfrac{\left(5 - 0\right) \times {10}^{- 3}}{\left(100 - 0\right) \times {10}^{- 6}} = 50$

${A}_{V} = \beta\dfrac{{R}_{C}}{{R}_{B}} = 50 \times \dfrac{60}{200} = 15$

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