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JEE Main 202127 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
27 August
Shift
Evening Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2021 · 27 August · Evening Shift · Physics · Semiconductors

A zener diode of power rating 2W is to be used as a voltage...

A zener diode of power rating 2W2W is to be used as a voltage regulator. If the zener diode has a breakdown of 10V10V and it has to regulate voltage fluctuated between 6V6V and 14V14V, the value of Rs{R}_{s} for safe operation should be _____ ΩΩ .

A zener diode of power rating 2W is to be used as a voltage regulator. If the zener diode has a breakdown of 10V and it

Correct answer

0

Step-by-step solution

For diode P=ViP = Vi

i=PV=210=0.2Ai = \dfrac{P}{V} = \dfrac{2}{10} = 0 . 2A

Now for Vs=14V{V}_{s} = 14V

Voltage drop across Rs=14−10=4V{R}_{s} = 14 - 10 = 4V

Thus, V=iRsV = {iR}_{s}

Rs=40.2=20Ω{R}_{s} = \dfrac{4}{0 . 2} = 20Ω

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