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JEE Main 202120 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
20 July
Shift
Morning Shift
Subject
Physics
Chapter
Semiconductors

JEE Main 2021 · 20 July · Morning Shift · Physics · Semiconductors

For the circuit shown below, calculate the value of I _ z :

For the circuit shown below, calculate the value of Iz:{I}_{z}:

For the circuit shown below, calculate the value of I _ z :

Options

  1. A25mA25mA
  2. B0.15A0 . 15A
  3. C0.1A0 . 1A
  4. D0.05A0 . 05A

Correct answer

A. 25mA25mA

Step-by-step solution

I=501000=50mAI = \dfrac{50}{1000} = 50mA

For the circuit shown below, calculate the value of I _ z :

I=502000=25mAI = \dfrac{50}{2000} = 25mA
IZ=I1000−I2000{I}_{Z} = {I}_{1000} - {I}_{2000}
=50−25=25mA= 50 - 25 = 25mA

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