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JEE Main202126 Feb 2021Morning ShiftPhysicsSemiconductorsActual

LED is constructed from G a - A s - P semiconducting material. The energy gap of this LED is 1 . 9 eV . Calculate the wavelength of light emitted and its colour. h = 6 . 63 × 10 - 34 J - s and c = 3 × 10 8 m s - 1

Options

  1. A654   nm and red colour
  2. B654   nm and orange colour
  3. C1046   nm and red colour
  4. D1046   nm and blue colour

Correct answer

A. 654   nm and red colour

Step-by-step solution

λ = h c E = 6 . 6 × 10 - 34 × 3 × 10 8 1 . 9 × 1 . 6 × 10 - 19 = 6 . 54 × 10 - 7 = 654   nm Red color

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