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JEE Main201910 Apr 2019Morning ShiftPhysicsSemiconductorsActual

An NPN transistor operates as a common emitter amplifier, with a power gain of 60 d B . The input circuit resistance is 100 Ω and the output load resistance is 10 k Ω . The common emitter current gain β is:

Options

  1. A6 × 10 2
  2. B10 2
  3. C10 4
  4. D60

Correct answer

B. 10 2

Step-by-step solution

A v × β = P gain   60 = 10 log 10 P P 0 P = 10 6 = β 2 × R out   R in   = β 2 × 10 4 100 β 2 = 10 4 β = 100 = 10 2

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