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JEE Main 201910 JanuaryMorning Shift

Exam: JEE Main
Year: 2019
Date: 10 January
Shift: Morning Shift
Subject: Physics
Chapter: Semiconductors

JEE Main 2019 · 10 January · Morning Shift · Physics · Semiconductors

To get output '1'at R, for the given logic gate circuit the input...

To get output

'1'at

R,

for the given logic gate circuit the input values must be:

To get output '1'at R, for the given logic gate circuit the input values must be:

Options

A $X = 1, Y = 1$
B $X = 0, Y = 0$
C $X = 0, Y = 1$
D $X = 1, Y = 0$

Correct answer

D. $X = 1, Y = 0$

Step-by-step solution

$R = \overset{¯}{( \overset{¯}{X} + Y ) + ( \overset{¯}{X ⋅ \overset{¯}{Y}} )} = ( \overset{¯}{\overset{¯}{X} + Y} ) ⋅ ( \overset{¯}{\overset{¯}{X . \overset{¯}{Y}}} ) = ( X . \overset{¯}{Y} ) ⋅ ( X . \overset{¯}{Y} ) = ( X . \overset{¯}{Y} )$

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