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JEE Main201815 Apr 2018Evening ShiftPhysicsSemiconductorsActual

Truth table for the given circuit will be

Options

  1. Aarray cc|c x & y & z 0 & 0 & 1 0 & 1 & 1 1 & 0 & 1 1 & 1 & 0 array
  2. Barray cc|c x & y & z 0 & 0 & 0 0 & 1 & 0 1 & 0 & 0 1 & 1 & 1 array
  3. Carray cc|c x & y & z 0 & 0 & 1 0 & 1 & 1 1 & 0 & 1 1 & 1 & 1 array
  4. Darray cc|c x & y & z 0 & 0 & 0 0 & 1 & 1 1 & 0 & 1 1 & 1 & 1 array

Correct answer

C. array cc|c x & y & z 0 & 0 & 1 0 & 1 & 1 1 & 0 & 1 1 & 1 & 1 array

Step-by-step solution

Truth table of the circuit is as follows array |c|c|c|c|c|c| x & y & x & a=x y & b= x y & z= a b 0 & 0 & 1 & 0 & 0 & 1 0 & 1 & 1 & 0 & 1 & 1 1 & 0 & 0 & 0 & 0 & 1 1 & 1 & 0 & 1 & 0 & 1 array

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