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JEE Main 20188 April
Exam
JEE Main
Year
2018
Date
8 April
Subject
Physics
Chapter
Semiconductors

JEE Main 2018 · 8 April · Physics · Semiconductors

The reading of the ammeter for a silicon diode in the given circuit...

The reading of the ammeter for a silicon diode in the given circuit is:

The reading of the ammeter for a silicon diode in the given circuit is:

Options

  1. A13.5mA13 .5 mA
  2. B00
  3. C15mA15mA
  4. D11.5mA11 .5 mA

Correct answer

D. 11.5mA11 .5 mA

Step-by-step solution

Given, R=200ΩR = 200Ω and V=3VV = 3V. We have to calculate the current. We know that, a potential barrier across silicon diode =0.7V= 0.7V.
The reading of the ammeter for a silicon diode in the given circuit is:

V=IRV = IR⇒I=3−0.7200=0.0115A=11.5mA⇒ I = \dfrac{3 - 0.7}{200} = 0 . 0115A = 11 . 5mA

So, the current is 11.5mA11 . 5mA.

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