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JEE Main 20178 AprilOnline
Exam
JEE Main
Year
2017
Date
8 April
Mode
Online
Subject
Physics
Chapter
Semiconductors

JEE Main 2017 · 8 April · Online · Physics · Semiconductors

The V - I characteristic of a diode is shown in the figure. The...

The V−IV - I characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is:

The V - I characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is:

Options

  1. A100100
  2. B106{10}^{6}
  3. C10−6{10}^{- 6}
  4. D1010

Correct answer

C. 10−6{10}^{- 6}

Step-by-step solution

Forward bias resistance R1=0.8−0.7(20−10)×10−3=0.110×10−3=10Ω{R}_{1} = \dfrac{0.8 - 0.7}{\left(20 - 10\right) \times {10}^{- 3}} = \dfrac{0.1}{10 \times {10}^{- 3}} = 10Ω.

Reverse bias resistanceR2=1010−6=107Ω{R}_{2} = \dfrac{10}{{10}^{- 6}} = {10}^{7}Ω.

R1R2=10−6\dfrac{{R}_{1}}{{R}_{2}} = {10}^{- 6}.
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