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JEE Main 20169 AprilOnline
Exam
JEE Main
Year
2016
Date
9 April
Mode
Online
Subject
Physics
Chapter
Semiconductors

JEE Main 2016 · 9 April · Online · Physics · Semiconductors

A Zener diode with a breakdown voltage of 4V is connected in series...

A Zener diode with a breakdown voltage of 4V4V is connected in series with a resistance RR to a battery of emf 10V10V. The maximum power dissipation rating for the Zener diode is 1W1W. The value of RR to ensure maximum power dissipation across the diode isA Zener diode with a breakdown voltage of 4V is connected in series with a resistance R to a battery of emf 10V . The

Options

  1. A12Ω12Ω
  2. B24Ω24Ω
  3. C36Ω36Ω
  4. D6Ω6Ω

Correct answer

B. 24Ω24Ω

Step-by-step solution

A Zener diode with a breakdown voltage of 4V is connected in series with a resistance R to a battery of emf 10V . The
Pzener=4i=1{\text{P}}_{\text{zener}} = 4i = 1

⇒i=14A⇒ i = \dfrac{1}{4}A

i=6R=14i = \dfrac{6}{R} = \dfrac{1}{4}

⇒R=24Ω⇒ R = 24Ω

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